EP_CAP P    f¥€ " Here's a more complicated example.~€ # In[2]:= Solve[x^5 + 3x + 1 == 0, x]}€ + Out[2]= {ToRules[Roots[3 x + x == -1, x]]}u€ B There is no way to get an exact, analytical, solution to a quintic^€ A equation like this. You can nevertheless ask Mathematica to give_€ @ you numerical results. You get the five complex number roots to`€ the equation.“€ In[3]:= N[%]”€ G Out[3]= {{x -> -0.839072 - 0.943852 I}, {x -> -0.839072 + 0.943852 I},Y€  >€ . {x -> -0.331989}, {x -> 1.00507 - 0.937259 I},l€  >€  {x -> 1.00507 + 0.937259 I}}É€ E�O+€N%€O+€N%€O+€Nõ‚OG€N €OG€N €OG€N €OG€N €OG€N €OG€N €OG€N¤€O