/*
 *  S W A P L P T S . C
 *
 *  COPYRIGHT (C) 1991 JOHN W GROTHMAN.  ALL RIGHTS RESERVED.
 *
 *  purpose:
 *		Swap LPT1 and LPT2.
 *
 *  to do:
 *
 *  technical notes:
 *		This is a SIMPLE thing to do.  Just swap the base I/O addresses
 *		in low DOS memory that DOS uses to map the LPT port hardware.
 *
 *  modification log:
 *	1.0		4/12/90		John W Grothman
 */

void main()
{
  int far		*lptr1 = (int far *)0x0408; /* Pointer to address of LPT1 */
  int far		*lptr2 = (int far *)0x040A; /* Pointer to address of LPT2 */
  unsigned int	lptbuf;

	lptbuf = *lptr1;				/* Save LPT1's base I/O address */
	*lptr1 = *lptr2;				/* Put LPT2's base addr into LPT1 */
	*lptr2 = lptbuf;				/* Put LPT1's base addr into LPT2 */
}